0≦θ≦πのとき、関数y=sinθ+√3cosθの最大値と最小値を求め,If f(θ)=∑_n=1^6cosec(θ+(n-1) π/4) cosec(θ+nπ/4), where 0θπ,θが鈍角のとき、sinθ=4分の3のときcosθとtanθの値を求めよ,Find f.f ''(θ) = sin(θ) + cos(θ), f(0) = 5, f '(0) = 4 - YouTube,1234! I Love Counting to the Number Four! #sesamestreet